Question

Two lines, OA←→OA↔ and OB←→OB↔, meet in a θ=63∘θ=63∘ angle at the origin OO in the x,y-plane. AA is on the positive x-axis and BB is in the first quadrant.

Light sent from point P=(11,4)P=(11,4) reflects off line OA←→OA↔ at point AA, then reflects off line OB←→OB↔ at point BB, then arrives at point Q=(11,7)Q=(11,7).

Where, exactly, are points AA and BB? Write each answer in Cartesian coordinates, accurate to at least three decimal places.

AA =    BB =

Answer 1

According to unformation, 1007) 4+ /I P (, 0 À 11.10) From geometry we see what un quadrilateral BFPA diaponals are meeting at 90°, which are normals or guiding ineflection in this case, so LEBA = 45= LEAR LO LPAC = 45° also kunits then, ACE PC a A = (7,0) Also, LDAB a uro and BRAP will be square them to, AP = BA a ur2 whit, in ABDA, 0p - D0 ( 01 со сол д) A zu uno. OD - OA-DA - 7-4-3 urib:

в – ( од соло, осо) О сол 0 = 1 од 22 Co, 62б on C 0 = со 6 см. (2 5 pdf unio То? (3 г. еt)