A force acting on an object moving along the x axis is given by Fx =...

Question

Question

A force acting on an object moving along the x axis is given by Fx = (3.0 – x) N where x is in m. Calculate the work done by

science physics

Answer 1

Answer #1

Ful (3.0 - ) 시 3) work done Ws Fuela 여 Day 수 (3-1)-(3) 올돌 =볼 W 300 a 9 W = 5 2T. 2 2 W=2J

Answer 2

Similar Homework Help Questions

A force acting on an object moving along the x axis is given by Fx =...

A force acting on an object moving along the x axis is given by Fx = (14x - 3.0x2) N where x is in m. How much work is done by this force as the object moves from x = -1 m to x = +2 m? +12J +42J +32J +28J -12J
The only force acting on a 2.6 kg body as it moves along the positive x...

The only force acting on a 2.6 kg body as it moves along the positive x axis has an x component Fx = −7x N, where x is in meters. The velocity of the body at x = 3.0 m is 8.2m/s. The only force acting on a 2.6 kg body as it moves along the positive x axis has an x component Fx =-7x N, where x is in meters. The velocity of the body at x = 3.0 m...
The only force acting on a 2.0 kg object moving along the x axis is shown....

The only force acting on a 2.0 kg object moving along the x axis is shown. If the velocity vx is -2.0 m/s at t = 0, what is the velocity in m/s at t = 3.0s?a. -2.0b. -4,0c. -3.0d. +1.0e. -5.0

The force acting on an object is given by Fy = (4x – 8) N, where...

The force acting on an object is given by Fy = (4x – 8) N, where x is in meters. (a) Choose the plot that best describes the force versus x from x = 0 to x = 3.00 m. F, (N) 20+ Fx (N) 20+ 104 IL x (m) 0,5 10 15 20 25 30 0,5 Lux (m) 10 15 20 25 30 -207 -20+ Fx (N) F(N) 20+ 207 101 x (m) Lux (m) 10 15 20 25...
The only force acting on a 1.8-kg body as it moves along the x axis is...

The only force acting on a 1.8-kg body as it moves along the x axis is given by Fx = -(3.0x) N, where x is in m. If the velocity of the body at x = 0 is vx = +8.0 m/s, at what value of x will the body have a velocity of +4.0 m/s?
A force acting on a particle moving in the x-y plane is given by F=2yi+x^2j N. The particle...

A force acting on a particle moving in the x-y plane is given by F=2yi+x^2j N, where x and y are in meters. The particle moves from the origin to a final position having the coordinates x=5 m and y=5 m and shown in the figure above. Calculate the work done by F along (a) OAC, (b) OBC, and (c) OC. (d) Is F a conservative or non-conservative force? Explain?

A 250 g block is moving along the “x” axis and at some point a force...

A 250 g block is moving along the “x” axis and at some point a force in the positive direction of the axis acts on it. The graph shows the magnitude of the force versus the position “x” of the particle. The curve is given by F=a/x^2, with a=9.0 N.m2 . Find the work done on the block by the force as the block moves from x=1.0 m to x=3.0 m by: a.) Estimating the work from the graph. b.)...
The only force acting on a 1.0-kg object moving along the x axis is shown. If...

The only force acting on a 1.0-kg object moving along the x axis is shown. If the velocity Vx is +2.0 m/s at t= 0, what is the velocity at t = 4.0 s? F. (N) 16 8 0 +(s) 21-3.1.4 -8 +6.0 m/s +5.0 m/s +2.0 m/s +4.0 m/s +7.0 m/s
The only force acting on a 2.0-kg object moving along the x axis is shown. If...

The only force acting on a 2.0-kg object moving along the x axis is shown. If the velocity Vx is +2.0 m/s at t = 0, what is the velocity at t = 4.0 s? +6.0 m/s +2.0 m/s +7.0 m/s +5.0 m/s +4.0 m/s

A force acting on a particle moving in the xy-plane is given by F = (2x3y4i+x2y3j)

A force acting on a particle moving in the xy-plane is given by F = (2x3y4i+x2y3j), where F is in newtons and x and y are in meters. The particle moves from the origin to a final position having coordinates x=5.00 m and y = 5.00 m as shown in the figure. Calculate the work W = F(r) dr done by F on the particle as it moves along a) The purple path b) The red path