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23. Lead (II) bromide is prepared using the following reaction: Pb(NO3)2 (aq) + KBr (aq) → PbBra(s) + KNO3(aq) (unbalanced) H
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Pb(NO3)2 (aq) + 2KBY(92) PbBr2 (s) + Z KNO3(aq) mol of PbBr2 150 sm 367001 g/mol 0.40870821 mol mol of Pb Bra mol of Pb(NO3)2

answered by: ANURANJAN SARSAM
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