Question

What volume, in liters, of 1.00 M KOH solution is needed to react completely with 0.100 L of a 3.00 M H₂SO₄ solution according to the following equation?

2KOH + H₂SO₄ → K₂SO₄ + 2H₂O

Answer 1

Answer

The volume of KOH in litres is 0.6 L

Explanation
Answer volume st kot solutions intitres tott Explanation . We are beingasked to calculate volume of Koh In liked that completebely Reating with 0.1ool of a 3.oom Hy son , Concentration of KoHz 1.00m - Balaned Reachon ý - 2KOH t hs04 - K₂SO4 + 2H2O This shows that we need 2 mols of kot for each Mode of Sulphuric and Fineling Moles of H Sora - - No. of Moles= Molarity & Volmame of dulin volme=o.lool Malarity z 3.00m Noof Mole a 3 - 00m X looL 0.3 Moles

Imole of Hy sou → znola of kot 0.3 moles of Hysay → 0.3 mole fly Soqx . < 2moles of kolt Imole of 1504 - - 0.6 mole of Kolt So there are obmols of koh finding volme from No of Moles and Motarity. Volume In libres = Nofrosto of Katz | Molant Koltz IM Molarity 0.6 mol im 0.6 mol 1 m/line = 0.6L = volme of the OH = 0.6L