Question

1. If you mixed 250.0 mL of 1.200% (w/v) fructoe (MW=180) solution with 600.0 mL of water. what would the concentration of fructose be in units of parts per million?

2. Suppose you had an alcoholic beverage with a concentration of 5.0%(w/v) ethyl acohol (MW=46.0). what is the molarity?

Answer 1

1. w/ concentration represents grams of solute present in 100 mL of solution. .. 100 mL 1.200 % (w/v) contains 1.200 g truetose → 250 ML 1.2007 (wy o 1.200* 250 - 100 g" . = 3 g fructose Abter addition of 600 mL water, there is 39 fruclose un (250 + 600) = 850 mL solution We have, paits pen million = mg of solute/ L of solution - 3x1000 mg 1:1g=10³ mg 850X10-3 L '11-10mL) = 3.529 x103 mg/l :. Concentration - 3.529 x109 ppm (1 ppm = 1 mg/L) 2. Hene, 5.0 g ethyl alcohol is present in 100 ml solution. is nosos 100 ml solution contain 59 solute. 46 g/mol → 1000 ml solution contain 5x1000 mol solute 100 X 46 = 1.087 mol solute :: Molarity - 1.087 M)