To evaporate or condense ammonia at its boiling point , it is a isothermal process.
For isothermal process
PV= nRT = constant - (As n,R,T are constant)
∆U = 0 and ∆H =0 because these are Temperature dependend.
So
∆U= Q-W = 0
Q= W
As q is given 23.30 kJ/mol.
Now
A.) W = 23.30 kJ /mol
B.) q = - 23.30 kJ / mol ( negative because heat is released)
C.) ∆U = 0
D.) ∆H = 0
2.44 Ammonia gas is condensed at its boiling point at 1.013 25 bar at -33.4°C by...
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