Question

CA CA9 Pari Part 6 der + mentProblemlD=115018216 TWCP - AP Physics 1 - Hampton Kendall : 0 tion a tots Constants Periodic Table Part A 455 placed between anden 1000 m What is ( F )the x-component of the net force exerted by these two charges on a third charge Your answer may be positive or negative, depending on the direction of the force Express your answer numerically in newtons to three significant figures View Available Hints) (F-1), - - 1.29. 10-6 Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining Next > Provide Feedback

Answer 1

I'm assuming positive x axis direction is along the right.

Given : charges are: a = -15.0 nC = 92 = 34.0 nC = -15.0 X10-9c. 34.0 X10-9 ce • q. is at position x = q2 is at position , x2 = - 1 - 730 m. Om Corigin). third charge charges, so q3 is at placed position between X₃, such Now, a the two that 9.3 = q3 ² 23 45.5nc = .45.5 x 10-9 c - 1 - 0 60m. , qz. az x = 0 x = -1.730 X = -1.060 (-) (+) (+). Using the Coulomb's law the electrostatic force on q3 due to q, is given by : 1E3) = K 19,931 en da where k = 9x109 40 X 68-854x10-12) and dai= 1(2-x) = (-1.060 (-1-730) i = 0.67 m. do LEZ, L = ( 9x109) x 1615.0X10-)X(45.5 X10-91 (0.672 = 1,368 X10-SN

The electrostatic force on qa due to a is. given by : (F3zl = K 123921 - duž where, der = 1x₂-x21 = 1-1.060-01 = 1:060 is the less (9x109) x145.5X10-99X (34.0X109 (14060.)? 5 1.239 x 10-5 N. Now, we know that same charges repel each other while opposite charges affract each other. q2 will repel ao and q. will. attract 93 Fizz (+) ct? 2 F31 93 Thus, both forces F32 and F31 are along same direction on came along left , ie... along -ve se quis. 9.2 . since the net force is along x axis only, the mother x-component of het force on 93. is given by a Enota 1 = 1 F32 lt Ifail =(1.239 X 10^s ) + ( 1.368 x 10-5). = 2.607 X10-5 N. But the force is along left ile. -ve x axis, - Free = -2-607 X10-S N

If you still have any confusion anywhere then please let me know in the comments section.

Thank you.