Question

Determine the magnitude and direction of the electric field strength at a point midway between a +5.0 HS charge and a -6.4 uc charge which are 12 cm apart.

Answer 1

re S. DE ws - Mwakasema to giuen q = 5.0 xlo b c 92 = -64 x 10-60 d = 12 cm = 0.12 m. a = d = 0.08 in - Electric fields emerges from I positive chance and terminates | towards negative change. • Elechic field at point p due to 1 q = +5.0u will be had a towards right (1. N =9x109 x 5 x loob (0106)2 = 12,500 x103 î nie) = 2.5 X 106 NCR S w hinweise

ve Electric field due to change 92 will also be towards right (1) I and magnitude is given by पत्र 2 = 9x109 x 614 X 106 (0.062 - 16.0 x 106 N/C Ep = 160 x 10o wie a Net Ě = Ep + Era = ( 160 +12.5) x 106 NIC À = 28.5 x 106 Nic (N) towards Right