Question

Two players are moving on a soccer field, each with their initial speed. They meet and have a collision. After contact, the players separate and each object moves with a post impact speed.
Data:
- Player weight 1 W1 = 887N
- Player 1 pre-impact speed V1i = 13.3 Kph at an angle = 25 degrees.
- Player weight 2 W2 = 1166N
- Player 2 pre-impact speed V2i = 11 at an angle of -33.9 degrees.
- There is a contact plane on the x axis.
-The coefficient of restitution is e = 0.36

Questions: (Please show procedure!)
1) Calculate the final speed of player 1 (magnitude and direction)
2) Calculate player 2's final speed (magnitude and direction)
3) Determine the change in energy of each object.
4) If the contact time between the players was tc = {tc} seconds, calculate the average impact force.

Answer 1

wi 887 N Wa = 11 66 gf and bu ma mass of players and playura mi thin 887 90.51 kg Wi cole 9.8 1 1 66 118.97 kg 9.8 13.3 kph 3.69 m/ 3.05 11 kph 0.36 (be foune collision 5 33.9° 25 Vai mi (aftur collision) op frog Iif

n- direction from consurvation of momentum in final momentum initial momentum m, Vif cose + m₂ Vze cos 33.9° my vie cosas + cos O2 m2 90.51 If cose, 90.51 x 3.69 C025' + 118.97 x 3.05 C0%(33.9) + 118.97 Vaf cosO₂ 603.86 90.51 gif coge, + 118.97 Jef coso, ya diruction of momentum in from conservation final momentum initial momentum - max m₂ af Simoa ma Vai Sin/33.9°) m, te Sin 25 If sina Sim (33.9°) 118.97 x 3.05 X go.51× 3.69 Simaro 90.51 Dis sind, 118.97 Vaf Simoz 61.23 go.51 118.97 af Sindz = Sino

Velocity of separation Velocity of apburoach four - divection m₂ daf cos Oz m, if coso, m₂ Vi i cos 33.90 m, vi cosao 0.36 90.51 Discoso, 118.97 V af cosO2 118x3.05 x COS33.9° 90.51 x 3.69 X 208 25° 0.544 118.97 dal costa 90.51 viscoso, 0.544 + go. 51 If coso, 118.97 Vaf cosaz put this im equation (" now + 603.86 90.51 if cose, 0.544 + 90.51 Vif cose, dif coso, 3.332 (iv)

four y direction m, vif Sino + ma Daf Simoz 0.36 my vie Simas + ma ze Sim (339) 90.51 Vf Sima + 118.97 Uzs Sinoz 123.67 123.67 90.51 Vif sino, 118.97 Vaf sinen now We but this in equation in 90.51 Vis Sime 123.67 + 90.51 Wifsimo, 61.23 Jef Simo, 1.021 (Ni) and adding (1) and (vi) om squarning 3 I cos²e + Sim²o, US (3.332)² + (1.021)? Sin²0, + cose, 1 (3. 3 3 2 ² + (1.021) 3.48 m2

now from (Ni) 3.48 Sino, 1.02L 17.06 1) kph 12.528 3.48 - 17.06 from equation (iii) 0.544 + 90.51% 3.48 C08(17.06) 118.97 Vaf cosO₂ (vii) Das cos O₂ 2.535 furom equation | now 118.97 Das sin 02 123.67 90.51 x 3.48 Sim (17.06) 0.262 (vii) af Simon

now 1 Sim? Oz + cog? 02) (0.262) + (2.535) 2.548 mly 011 9.17 КРЬ mow from equation (vii) Coro 2.535 2.548 0.99 82 1 3) of first in energy change pelayur is 2 2 Ima mi DE, 2. 2 1 1x goose | (3-69)? 15.48)) DE, 2. 68.14 Joule DE,

DE2 m3 I dae DE2 x 118.97 (03.05) ? – (2.548)*) Joule DEZ 167.16 4) Impulse change in momentum OP Fource x time Faite AP AP mi ve m, vif F = de to 90.51 ( 3.69 - 3. 48) L to 19 Newton te