Question

Can you help me to do the calculation and graph for two tables? thank you

mass = 100g

ANALYSIS AND QUESTIONS: 1. Plot a graph of the wavelength versus the inverse of the frequency, 11f. Draw a "best-fit" straight line and determine the slope. 2. Determine the tension of the string from knowledge of the slope. 3. Compute the velocity v of the wave in the string using Eqn. (2). 4. As the frequency is increased, what happens to the velocity of the wave?

Answer 1

Remember that: 1 2L L=1 +1= For the first table: n lambda vs 1/f f(Hz) 1/6 \lambda 15 0.066667 1.13 22.5 0.044444 0.678 17.5 0.057143 0.8475 27.5 0.036364 0.565 y = 17.95 -0.1131 0.02 0.04 0.06 0.08 Remember that: 1 = = v the slope represents the velocity of the wave. In this case: v = 17.95 Also: v= The tension force is: Fy = uv2 = (0.0042)(17.95)2 = 1.35 N If the frequency increase and the tension does not change, the velocity wont change. For the second table: n lambda vs 1/f f(Hz) 1/f \ambda 42.5 0.023529 1.13 57.5 0.017391 0.8475 7 0 0.014286 0.678 82.5 0.012121 0.565 y = 49.489x -0.0279 5 0 0.005 0.01 0.015 0.02 0.025 The velocity is: V = 49.49" The tension force is: Fr = uv2 = (3.06 * 10-4)(49.49)2 = 0.749 N