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Nested loops

1. Request an odd integer value between 10 and 20. Input should be validated until correct. Use a nested loop to output the b

c++ nested loops

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Answer #1

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#include <iostream>

using namespace std;

int main() {

int n ;

do{

cout<<"Enter an odd integer between 10 and 20: ";

cin>>n;

}while((n>20)&&(n<10));

char a[n][n];

for(int i=0;i<n;i++)

{

for(int j=0;j<n;j++)

{

if((i==0)||(j==0)||(i==(n-1))||(j==(n-1)))a[i][j]='X';

else if(i==j)

{

a[i][j]='X';

}

else if ((i+j)==(n-1))

{

a[i][j]='X';

}

else

{

a[i][j]='-';

}

}

}

for(int i=0;i<n;i++)

{

for(int j=0;j<n;j++)

{

cout<<a[i][j]<<" ";

}

cout<<endl;

}

  return 0;

}

C++14 14 Shortcuts S Reset Copy for(int j=0; j<n; j++) if((i==0)||(j==0)||(i==(n-1))||(j==(n-1)))a[i]: else if(i==j) 15 - a[i

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