Question

1. Determine the number of moles of reagent in the following solutions: a. 25.00 mL of 0.10 M acetic acid b. 5.55 mL of 0.092 M NaOH C. 0.50 mL of 0.087 M HCI 2. A buffer solution contains 0.120 M acetic acid and 0.150 M sodium acetate. a. How many moles of acetic acid and of sodium acetate are present in 50.0 mL of solution? b. If we add 5.55 mL of 0.092 M NaOH to the solution in part a., how many moles of acetic acid, sodium acetate, and NaOH will be present after the reaction is done? c. If we add 0.50 mL of 0.087 M HCl to the solution in part a., how many moles of acetic acid, sodium acetate, and HCl will be present after the reaction is done? 3. Determine the pH you expect to find for the three solutions in question 2.

Answer 1

solution • @ 25.00 me of 0.1om acetic acid mole is given by, mole = molarity & volume of solution (inL) 0:10 M X 25.00 x 103L 022 99999P?? = 25.00*10-4 mole mole = 2.5x103 mole. 6 5:55 mL of 0.092m NaOH (in L. mole = molarity & volume of solution = 0,092 X 5.55 X10-3(L) - 5.18 10-4 mole 7 © 0.50 mL of 0.087M HU mole = molarity & volume of solution (inu. = 0.087 x 0.50X10-3 = 4.35*105 mole.