Question

Circular blanks (slugs) of 1100AI, diameter d = 25 mm and thickness h = 3 mm, are to be mass- produced as the starting material for toothpaste-tube extrusion. The available presses are of 500 N capacity and can take a maximum 220 mm wide strip. Economy of material utilization increases with increasing number of rows cut from one strip width. (a) Calculate the torque required for blanking a single slug. (b) Estimate the number of slugs that can be blanked simultaneously with the available press. (c) Suggest the optimum layout for the slugs if the web (remaining material between cuts at edges) is approximately h, but seldom less than 1 mm.

Answer 1

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Solution fo Aluminium (9) calculating 1100, Shear strength = 69 Nuit punching force (F) F = Tdt 8 69 XX 25 X3 X69 F = 16.264 KN / slug (bo) press capacity = 500 KN Number of stugs - capacity - 500 16.264 = 3007427 Number of slugs = 30.7427 Thus, Slugs can be Blanked simultaneously.

(C. Maximum of 30 slugs can be punched with the pres. we can arrange 30 slogs into 5x6 matrix with immgapi between Adjecent holes db Stymo 1 mm - = 50+4 calculate the total width = 5x2574 = 129mm total longth - I - Calculate 6d+5 = 6x25+5 = 155 mm Therefore, The Layout Dimension for optimization is (155X 129) mm2,