Question

A ball is dropped from rest at a height h. Directly below on the ground, a second ball is simultaneously t thrown upwards with a speed of vc. The two balls collide at the moment that the second ball is instantaneously at rest. (They collide when the second ball is at its maximum height.) What is the height of the collision? At what time does the collision occur if both balls' motion stated at t = 0 s?

Answer 1

a) consider the second ball the final velocity = 0 initial velocity = Vv_0 Collide at a time = t Mu difference traced = h_1 at collide from the equation v^2 - u^2 = 2 as 0 - v^2_0 = 2(-9) h_1 h_1 = v^2_0/2g Height of collide h = v^2_0/2g b) The first ball initial velocity = 0 the equation s = ut + 1/2 at^2 (h - h_1) = 0 + 1/2 gt^2 t^= 2(h - h_1)/g t = squareroot 2(h - h_1)/g