Two identical negative charges (Q, & Q2) are positioned as shown (coordinates seen). A positive test...

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Question

Two identical negative charges (Q, & Q2) are positioned as shown (coordinates seen). A positive test charge qo is placed at p

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Answer 1

Answer #1

Let the charges be Q1 = Q2 = -Q

The two negative charges attract the positive test charge q0 with the same force

$F = - \frac{kQq_0}{r^2}$

where r is the distance between the test charge and one of the negative charges

and r2 = x2 + y2

Both the negative charges attract the test charge towards them with the same force F,

Each force F will have two components, $Fcos \theta \ and \ Fsin \theta$

$Fsin \theta$ components cancel each other as they are in opposite directions

thus net force on the test charge will be downwards , that is in the negative y - axis direction

Eino Pro 6g> Esino Eno) Gno)

Answer 2

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