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Let S be a nonempty set and ⋆ be an operation on S. If ⋆ on...

Let S be a nonempty set and ⋆ be an operation on S. If ⋆ on S is commutative and S′ ⊂ S is closed with respect to ⋆, is ⋆ on S′ commutative? Prove why or why not.

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solution in * be let s be non emply set and an operation on s. If s is commutative. scs is closed with respect on to *. then

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