Question

Exercise 9.7 

The angle \(\theta\) through which a disk drive turns is given by \(\theta(t)=a+b t-c t^{3}\), where \(a, b\) and \(c\) are constants, \(t\) is in seconds, and \(\theta\) is in radians. When \(t=0, \theta=\pi / 4 \mathrm{rad}\) and the angular velocity is \(1.70 \mathrm{rad} / \mathrm{s}\), and when \(1.70 \mathrm{~s}\), the angular acceleration is \(1.35 \mathrm{rad} / \mathrm{s}^{2}\).

Part E

What is θ when the angular acceleration is 2.50 rad/s²?

Part F

What is the angular velocity when the angular acceleration is  2.50 rad/s²?

Answer 1

delsprad/.sv ak七ㄈㄧ兆) 60 at dt 2.50 6Go (3238) t