What is the formal charge (FC) on nitrogen (N) in ammonium cation (NH4+)?
Group of answer choices
0
+1
–1
None of the above
The lewis structure of NH4+ is

The formula of formal charge is:
Formal charge = [# of valence electrons] – [electrons in lone pairs + 1/2 the number of bonding electrons]
on N:
# of valence electrons for N = 5
Formal charge =5 - (0 + 1/2 * 8)
= 5 - 4
= +1
Answer: +1
What is the formal charge (FC) on nitrogen (N) in ammonium cation (NH4+)? Group of answer...
What happens to the extra electron in NH4+? When calculating formal charge, does it get ignored? I know a simple formula to arrive at the answer of a +1 formal charge on Nitrogen, but I want to know what happens to that extra electron from the free atom when Nitrogen had 5 electrons.
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Hi, I'm trying to understand how oxygen and nitrogen, when in a molecule with 4 bonds to them, for example, NH4+ and H3O+ bear a POSITIVE charge when they gain that additional proton? I think I understand that nitrogen's FC would be calculated 5-0-4= +1, but now, I'm having the same problem with nitrogen because wouldn't the formal charge be calculated 6-3-3=0?? Do I have the formula wrong? What is GOING ON!!?