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150 N Problem 4 (8 Marks) [ILOs: K1, 12, P.]] 100 N --- 2m 1.5 m 50 N .... For the shown frame, determine the horizontal | a

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150 sints 150 75000sts TE 1459 1. 5m HA y = 2x S30 2 = 2605 30 a = 7732 y = 1. 56545° due to Ds = 3m tre -3; -m - = 3x 3 +(2Moment at internal hinge B from left side RAX 1.732 - HAX (2+1) - 50%1 -100x1.732 = 0 1.732RA - 3 HA = 223.205 - Moment at inNow from 0 ② 4 Re -156.067 - HA = -1506545° -6.067 RA - 156.067 -HA = -150 caruso HA + RA = - 56.068 - 5 Using ② & G 1732 RA& fn =0 Hp + 50 = 67069 = 17.69 KN Efy = 0 11-623 +RB = 100 11.623 RB = 88-377 KN ITs scanned with Care Scanner

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