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4) a. A signal g(t) = 20 cos 50nt.cos 220nt is sampled by a pulse train of frequency 250Hz. i. Calculate the Nyquist rate for
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given signal 96) = Qocol 507ft. 6o9 220 TL 20 col 2207Tt · Col 507Tt 0 cosa Cobb cola cosb cos (a-b) + cos (atb) 2 * [cs (g0tcos 270t col 170 TE: 2 الد وی اد fi - wi OTT fy We 2T EN 135 270TL शो fy = 170 T 2# fi 135 eer = 85 Nyquist Sampling 30 2x HeCett-off frequency of LILIT 385 -335 -185-135 -85 85 135 335 +385 -250 250 sampled sequal fs= 450HZ; The follow following freN al tor N = Transmission Bandwidth B = NS 7x7.5 KHZ 52-5 KHZ ( SONR) tra de 6-02XN + lo 7609 6.02X 7 + 1.7609 = 42.14 f 1*76

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