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The element X has three naturally occurring isotopes. The masses (amu) and % abundances of the...
the element X has naturally occurring isotope. The masses (amu) and % abundance of the isotopes are given below. the average atomic mass of the element is ? Isotope: 221X, 220X, 218 X Abundance: 74.22, 12.78, 13.00 Mass: 220.9, 220.0, 218.1
The element carbon has two naturally occurring isotopes. The isotopic masses and abundances of these isotopes are shown in the table below. Isotope 12c isotopic mass (amu) Abundance (%) 12.00 13.00 98.93 1.07 Calculate the average atomic mass of carbon to two digits after the decimal point. Number = _______ amu
A hypothetical element (atomic mass = 17.144 amu) has three naturally occurring isotopes with isotopic masses and natural abundances given below. Calculate the percent abundance of Isotope 1 Isotope Mass(amu) Abundance(%) 1 15.12326 ---- 2 16.13192 ---- 3 20.16658 29.60
An element has three naturally occurring isotopes with masses as listed below. The average atomic mass of this element is 28.08 amu. Determine the two missing percent abundances.^28X 27.98 amu % abundance =^29X 28.98 amu % abundance = 4.68 %^30X 29.97 amu % abundance =
The element chlorine has two naturally occurring isotopes. The isotopic masses and abundances of these isotopes are shown in the table. Isotope Isotopic mass (u) Abundance (%) Cl35Cl35 34.97 75.77 Cl37Cl37 36.97 24.23 Calculate the average atomic mass of chlorine to two digits after the decimal point. can someone explain how to do this and the solve it.
The element Oxygen consists of three naturally occurring isotopes with masses 15.949915, 16.999131, and 17.999159 amu. The relative abundances of these three isotopes are 99.76, 0.03800, and 0.2000 percent, respectively. From these data calculate the average atomic mass of Oxygen (in amu).
An element has three naturally occurring isotopes with the following masses and abundances (in parenthesis): 27.977 amu (0.9222); 28.974 amu (0.0469); 29.974 amu (0.0310). Calculate the atomic weight of the element. a. 28.09 amu b. 66.94 amu c. 86.93 amu d. 29.98 amu
2. An element has 2 naturally occurring isotopes with the following masses and abundances A. Calculate the atomic weight of the element. (20 pts) Isotope mass Percentage 34.97 amu 75.78% 36.97 amu 24.22% B. What is the element? C. How many neutrons does the heavier isotope have? (Round to whole number) D. How many electrons does the element have? E. What type(metal/nonmetal) of element is it? F. If the element above gains 1 electron what neutral element has the some...
An unknown element (Element X) has three naturally occurring isotopes. Complete the table by filling in the missing percent abundance (2 decimal places). Then calculate the atomic mass of element X (1 decimal place) and determine its identity by filling in its atomic symbol (case sensitive). Isotope Abundance (%) Atomic Mass (amu) 23.985042 1 78.99 2 24.985837 10.00 3 25.982593 amu Atomic mass of element X (1 decimal place): Atomic symbol of element X:
UITGUIC Potassium has three naturally occurring isotopes. They are "K (93.26%, ? amu), "K (0.0117%, 39.964 amu), and 4K (6.73%, 40.962 amu) Calculate the atomic mass of the potassium-39 isotope given that the weighted average of the isotopes is 39.099 amu and using the percent abundances of all the isotopes and the atomic masses of potassium- 40 and potassium-41. Express the mass to three decimal places and include the appropriate units. Submit Request Answer