mass of the box = 93/9.8 = 9.5 kg
acceleration ax = 0.9 m/s^2
along horizontal Fnet = Fx - fx = m*ax
fx = Fx - m*ax
frictional force fx = 20-(9.5*0.9) = 11.45 N
<---ANSWER
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part (b)
along vertical
n - Fy - W = 0
normal force n = W + Fy = 93 + 25 = 118 N <<---ANSWER
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