Question

6. In 2007 the scores on the College Aptitude Test (C. A.T.) were distributed normally with mean 500 and standard deviation 60, briefly N (500, 60). Find the 75th percentile for the CAT. 520.0000 605.4431 458.1174 540.4694 D7 In 2007 the scores on the College Aptitude Test (C. A.T.) were distributed normally with mean 500 and standard deviation 60, briefly N (500, 60). Find the Z score for a CAT score of 450. -.5631 -.8333 .6733 1.0833

Answer 1

Answer:

6.

Given,

Mean = 500

Standard deviation = 60

P(X < x) = 0.75

P((x-u)/s < (x - 500)/60) = 0.75

since from standard normal table

z = 0.6745

(x - 500)/60 = 0.6745

x - 500 = 0.6745*60

x = 540.4694

Option D

7.

Given,

Mean = 500

Standard deviation = 60

z = (x - u)/s

= (450 - 500)/60

= -50/60

= - 0.8333

Option B