3) Electrons are accelerated so that their de Brogue wavelength is 83 pm = 0.083 nm....

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Image for 3) Electrons are accelerated so that their de Brogue wavelength is 83 pm = 0.083 nm. What is the kinetic energ

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Answer 1

Answer #1

debroglie wavelenght L=h/sqrt(2mK)

Kinetic energy K =h^2/2mL^2 = (6.625x10^-34 Js )^2/(2*9.1*10^-31 kg *[0.083x10^-9]^2)

K =350x10^-19 J (1 eV/1.6x10^-19 J) =218.75 eV

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for second exited state is n = 3

E = 13.6 eV/ n^2 = 13.6 eV/ 9 = 1.51eV

longest wavelength is

lamda = hc/ del E = 1240 eV*nm/ 1.51 eV = 821.19 nm

Answer 2

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