Question

1.Determine the bond order in a molecule or ion with 10 valence electrons.

Express your answer using two significant figures.

2.Determine the bond order in a molecule or ion with 13 valence electrons.

Express your answer using two significant figures.

3.Determine the bond order in a molecule or ion with 14 valence electrons.

Express your answer using two significant figures.

4.

Answer 1

1. A molecule/ion with 10 valence electrons The outer electronic configuration of a molecule with 10 valence electrons is as follows: The formula to calculate the bond order is as follows: Bondorder-_(Electrons in BMO-Electronsin ABMO) Here. BMO- Bonding molecular orbitals, ABMO Antibonding molecular orbitals. Bondorder-(8-2) -3.0 Therefore, the bond order of the molecule/ion with 10 valence electrons is 3.0. 2. A molecule/ion with 13 valence electrons The outer electronic configuration of a molecule/ion with 13 valence electrons is as follows: Bond order=-(8-5 =1.5 Therefore, the bond order of the molecule/ion with 13 valence electrons is 1.5

3. A molecule/ion with 14 valence electrons The outer electronic configuration of a molecule/ion with 14 valence electrons is as follows: Bond order-(8-6) Therefore, the bond order of the molecule/ion with 13 valence electrons is 1.0 4. A species with unpaired electrons are said to be paramagnetic and are attracted by the external magnetic field.

The outer electronic configuration of a molecule with 10 valence electrons is σ2.2ơ2.2σ2p, 2 π2p 2 π2p 2 . This molecule does not possess any unpaired electrons. Hence, it is diamagnetic.

The outer electronic configuration of a molecule with 12 valence electrons is 0% σ2s2 σ2p, π2p, π2p π2 h, "this molecule possesses two unpaired electrons Hence, it is paramagnetic.

The outer electronic configuration of a molecule with 13 valence electrons is σ2:2ơ2s2Cm2 π2p 2 π2p 2π.2p. Hence, it is paramagnetic. 2π.,. This molecule possessesoneunpairedelectron. The outer electronic configuration of a molecule with 14 valence electrons is σ2:2ơ2:2σ2n2 π2p 2 π2p 2πα 2π.2p 2 . This molecule does not possess any unpaired electrons. Hence, it is diamagnetic.

Diamagnetic Paramagnetic 10 valence electrons 12 valence electrons 14 valence electrons 13 valence electrons