Question

-49 m- H = 12 m 33 m ZAVAVAWZWZZAVAZAVI R AVANVIAVAVAVAWIWMVMVAVI VAIVAA av Elevations: Zo = 0 (all upstream ground surface) Zx = -0.5 m (all downstream ground surface) ZA = -30 m ZP = -18 m Zc =-2 m 2 = -4 m ZE = -9m Soil properties: Gs = 2.7 e = 0.6 k=8. 104cm/s Assuming that the drawing is to scale, calculate: a) The daily discharge Q b) The water pressure at point C c) The difference in head between points B and D d) The maximum exit gradient e) The factor of safety against piping

Answer 1

g 49 m. 되어 12.5 A A Jatt NH 33m. I Z dit zo Ze= -0.5m. ZA=-30m , Z BT ISM, Z = -2m, ZD=-4m ,ZE=-gm. 49227e-0.6 K=8x10cm/sec = 88186 m/s Ne = No oq flow lines -l.. . 36-1-5 Flow channels: 1 No = No. q potential props, = 16 - Head causing How = 12.5 m a) The Daily Dischargle ( = K.H. Noen x unit lengtheim) = 8x108x12+5 x 2 1 1 = 3.125x10-5 m/sec/m.

AHH 12.5 ET: -0.78125 m. - 6 The water pressure at point c. -- це + речка. Р - Yр., hp pressure head hp = Total head - Elevation head Total head @ C = H - NAH 12:5-900178125) = 5.468 ~ 504 up to o 19 props and hos Total head @C – Elevation head@C Z=- 2m Trib. 5.4-1-21 = 7.9 m. point @ water pressure at = 9.81*7.4 i Dei = 78.594 kalimin

© Difference in points BfD Total head @ B=H-nah no. q Drops - up to B=5 = 12.5-5(0.78124) = 8.59 ~ 8.6m. Total head @ D =H-NAH -1205-1560.78125) = 0.78125 m nog srops up to b= 15 blw in head points B &D Difference = 8.6 -0.078125 = 7.82 m o the maximum exit gradients . : Ab head @ 0.78125 enit AL7 - 2D + 4 = o.195 -e factor safety against piping critical - Gule - 2.7 - 12 =10625 factor of safety against piping Critical lexit - 1.0625 0.195 5448