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40.00 mL of 0.300 M HBr is titrated with 0.300 M NaOH. What is the pH...

40.00 mL of 0.300 M HBr is titrated with 0.300 M NaOH.

What is the pH of the initial HBr solution? First determine the concentration of H+ in this solution.

Then, determine the pH of the solution, based on the H+ concentration.

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Answer #1

A) initial concentration calculation:

   [H+] = 40.00 mL x 10-3 L x 0.300 M = 0.012 M

   [OH-] = 0.300 M     (Volume is not specified, hence i assume it is 1 L solution stock)

B) Only initial pH can be calculated from given data, since volme of NaOH is not specified

[H+] =0.012 M;    pH = -log [H+] = -log [0.012] = 1.92

pH of the initial HBr solution pH = 1.92

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