40.00 mL of 0.300 M HBr is titrated with 0.300 M NaOH.
What is the pH of the initial HBr solution? First determine the concentration of H+ in this solution.
Then, determine the pH of the solution, based on the H+ concentration.
A) initial concentration calculation:
[H+] = 40.00 mL x 10-3 L x 0.300 M = 0.012 M
[OH-] = 0.300 M (Volume is not specified, hence i assume it is 1 L solution stock)
B) Only initial pH can be calculated from given data, since volme of NaOH is not specified
[H+] =0.012 M; pH = -log [H+] = -log [0.012] = 1.92
pH of the initial HBr solution pH = 1.92
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