Confidence interval for Population mean is given as below:
Confidence interval = Xbar ± Z*σ/sqrt(n)
From given data, we have
Xbar = 20
σ = 10
n = 64
Confidence level = 99%
Critical Z value = 2.5758
(by using z-table)
Confidence interval = Xbar ± Z*σ/sqrt(n)
Confidence interval = 20 ± 2.5758*10/sqrt(64)
Confidence interval = 20 ± 3.2198
Lower limit = 20 - 3.2198 = 16.7802
Upper limit = 20 + 3.2198 = 23.2198
Confidence interval = (16.7802, 23.2198)
The sample size formula is given as below:
n = (Z*σ/E)^2
We are given
σ = 10
Confidence level = 99%
Critical Z value = 2.5758
(by using z-table)
Margin of error = E = 0.5
The sample size is given as below:
n = (Z*σ/E)^2
n = (2.5758*10/0.5)^2
n = 2653.898256
Required sample size = 2654
• For Example 1, Calculate the Sample Size Reqiured for a margin of error of only...
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Please show all work!!!
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To calculate a confidence interval, the margin of error (E) must first be calculated. The Margin of Error, E, for means is: E = 1.96*s/sqrt(n), where s is the sample standard deviation, n is the sample size. The “sqrt” stands for square root. The Margin of Error, E, for proportions is: E = 1.96*sqrt[p*(1-p)/n], where s is the sample standard deviation, n is the sample size, and p is the proportion. Use the Confidence Interval formula above, and the correct...