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From an initial mix of: 2 mol Cl2, 1 mol Br2, 0.5 mol I2, 0.5 mol...

From an initial mix of: 2 mol Cl2, 1 mol Br2, 0.5 mol I2, 0.5 mol Cl−, 1 mol Br−, & 2 mol I−; the total quantity of Br−  present after all possible reactions occur is:

A)1.5 mol
B) 1 mol
C) 0.5 mol
D) 0 mol
0 0
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Answer #1

Cl2 reacts with Br-

Cl2 + 2Br- --> Br2 + 2Cl-

1 mole of chlorine requires 2 moles of Br- ( but there is only 1 mole of Br-)

Hence this requires 0.5 moles of Chlorine which is availabel. Hence, all the Br- is consumed.

1 mole of Br- is consumed ( limiting reactant) and 0.5 mol of Cl2 is consued

and Br2 reacts with I2

Br2 + 2I2 --> I2 + 2Br- (2)

I2 is the limiting reactant and Br2 is excess

0.5 mole of I2 produces 0.5 moles of Br-

Br- present = 0.5 mol

C is the correct aswer

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