Question

A simple pendulum is 2.00 m long. (a) What is the period of small oscillations for this pendulum if it is located in an elevator accelerating upward at 6.00 m/s2? s (b) What is the period of small oscillations for this pendulum if it is located in an elevator accelerating downward at 6.00 m/s2? s (c) What is the period of this pendulum if it is placed in a truck that is accelerating horizontally at 6.00 m/s2?

please answer this if you know its right

Answer 1

The time period is, The elevator is accelerating upwards The acceleration acting on the pendulum is, a = (9.8 +6.00) m/s2 = 15.8 m/s2 15.8 m/s 2.23 s The elevator is accelerating downwards The acceleration acting on the pendulum is, a (9.8-6.00) m/s -3.8 m/s2 T =2π 3.8 m/s2 = 4.56 s The resultant horizontal acceleration of the truck is, a 98 m/s)+(6) -11.49 m/s T =2π 11.49 m/s2 = 2.62 s