Question

BICH 410 Fall 2019 Assignment 1 115 points Due at the beginning of Class, Friday, Sept. 6 21.) Consider the standard free energies shown below(T -37 °C, R-8.3145 J/mole-K): UDP-Glucuronate + H20 1-Phosphoglucuronate + UMP + 2H AG"=-36.9 kJ/mol UTP + H2O - UMP + PPi + 2H AG = -32.5 kJ/mol PPi + H20 - 2Pi AG" = -33.6 kJ/mol (A) (3 pts) Calculate AG & Ko' for the following reaction. 1-Phosphoglucuronate + UTP+H30 - UDP-Glucuronate + 2Pi (B) (2 pts) Which of the following statements best describe this reaction? (A) The reaction is irreversible under standard conditions. (B) The reaction is reversible under standard conditions. (C) The reaction is at equilibrium under intracellular conditions. (D) The reaction is reversible under intracellular conditions. (E)K'eq = 0 (C) (2 pts) This reaction is catalyzed by phosphoglucuronate pyrophosphorylase. How would this enzyme effect AGº' and Koq”?

Answer 1

Reverse eq - 0 IPhosp tump + 2H+ UDP + Gluetho = 36g.) UTP 4,0 ±UMP PR +2 = -32.5. Ppit H₂0 2P; = - 33.6 -05p UTP H, 0 - > 00P +GhlU+ 2 6 Do = -29.2 Kg/mol - - 27 2 Dao = – 2.303 RT log K log k = +29.2x103 2.303 X 8.314x310. look = 4.919 k=8.30x109

B) statement B is correct AS that is reaction is reversible under standard equations as delta G is negative

C) catalyst doesnot affect Keq

it only decreases the time to reach equilibrium

BECAUSE DELTA G = RTln Keq