Below are the null and alternative Hypothesis,
Null Hypothesis, H0: μ <= 35
Alternative Hypothesis, Ha: μ > 35
Test statistic,
z = (xbar - mu)/(sigma/sqrt(n))
z = (38 - 35)/(8/sqrt(30))
z = 2.05
P-value Approach
P-value = 0.0202
As P-value < 0.05, reject the null hypothesis.
There is sufficient evidence to conclude that the mean
custromers are greater than 35.
Investigation does not support the claim.
Australia Post claims that the mean daily number of customers at a particular branch is 35...
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