Question

en Zand nice za Tech 601 2019 AM Name: top pico) Innan 1010 ricromi e 10 1 0 104 Mimega) Gigiga Tetra petal 10 10 10 10 10 coulomb is charge carried by 6.25*10electrons 1 9 V Pwatt) Windo Vi = 1R Efficiency-Port Phone Power Point TE T TE K 3. 15 points. Find the following values: At to Si=closed 52-open At t-40 ms S1-open 52 closed a. The instantaneous value of the voltage across the capacitor at ta5 ms b. The instantaneous value of the voltage across the capacitor at t-63 msad t-200m S2 O Key-A 2k0 Key A V1 4F = 12V R2 w 40

Answer 1

As for source is connected, the txo , no voltage . (01)-ov * circuit for too R + zka = 12v v q yutta - R2 ww YkN I figli) Vclot)= V(o)zov as voltage across capacitor sa cannot change abruptly. circuit for t=oot (assuming switch s, is closed 1 and Sy is open till trot = R 2 Km y 12V Krat) Vc Cost) = 12V Scanned with CamScanner

Complete response is given by: CH) = vacao + [v(0) -100.Jētie véloo) = final capacitor volteye \(o)= initial capacitor voltage z= time constant Re = (2.x103)(4x106) = 8x163 y(t) = 12-12 25/8x103 Telt) = 12-126 1256 value at t= 5msec victimsec) = 12-12 €125*5X163 1 = 12-126 0.625 Yalt= msec) = 5.5768 Velt Scanned with CamScanner

Valt=40 msec)= 12-12 e 125x40 velt=40 msec) ¥ 12 circuit for t>40 msec: C Yelt) Mur ta R2 Scanned with CamScanner 4 kr

a The voltage equation for t340 :- Vect) = “Co)-[xco) - vsuombeey] ēt 7-(+-40x103)/2 "COO) = 0 Vc140): 12V z=re = 4x108x4 x 103 2= 16x103 + V ) = 0 - [o - 1272 - 092/s xls -62.5 (t-0.04) - 12 e -> valt) at t= 63 mal = 0.063 sec 'c(t =63 msec) = 12 62.5 (0.063 - 0.04) 21.4375 Tvelt = 63 msec) = 2.85 volt Velt) at t=200 msec = 0.2 sec Valt=200 msec) = 12 €62.5 (0.2-0.04) = 12e-10 = 4.54 X1005 Is Scanned with alt=200mce) o volt CamScannda )