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Reminder: No collision is truly elastic! assume cart 1 has mass 234 g and initial velocity...

Reminder: No collision is truly elastic!

assume cart 1 has mass 234 g and initial velocity +v10 = 7.6 m/s, and cart 2 has mass 897 g. Assume the track is frictionless, and after the "elastic" collision cart 1 is moving at v1 = -4.362 m/s and cart 2 is moving at v2 = 3.035 m/s.

What percentage of the original linear momentum was "lost" due to external forces? (Remember: linear momentum is a vector!)

i am not asking for the lost of energy and i already got 5.97 %for lost of energy . This question is actually asking to calculate the lost of monmentum . Please read the question before answering it.

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Answer #1

initial momentum

m1v1 + m2v2 = 1.7784

final

m1v1 + m2v2 = 1.701687

dP = pf-pi/pi

= -4.3136 %

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