2) applying rule 13 for hydrocarbon
General formula for hydrocarbon = CnHn+r
n= number of carbon atom
r = remainder
Step1: devide the molecular weight by 13.
176/13= 13.5385
That is number of carbon atom (n) = 13
Step2: multiply the remainder by 13.
13 × 0.5385 = 7.0005~ 7
Therefore number of hydrocarbon = n + r = 13+ 7 =20
Step3 : hydrocarbon formula
C13H20
Step4 : since molecular weight and number of hydrogen atom is even. Threfore there is possibility of oxygen atom.
For each oxygen atom replace CH4.
Hence molecular formulas containing oxygen atom are given as
C12H16O , C11H12O2
Hence three reasonable molecular formulas
C13H20 , C12H16O , C11H12O2.
Propose three reasonable molecular formulas for a molecular ion at m/z = 176, (show calculations; 3...
Propose three reasonable molecular formulas for a molecular ion at m/z=152.
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