Question

WRITE A CODE IN C++

A CLASS WITH MEMBER FUCNTIONS THAT COUNTS THE LINES OF CODE OF C++ FILE OR TEXT FILE .COMMENTS SHOULD NOT BE COUNTED AND SPACE BETWEEN LINES OF CODE SHOULD BE IGNORED AS WELL. ASK FOR INPUT FROM THE USER IT CAN BE CPP FILE OR TEXT FILE

Assignment:Write a program to count lines of code according to your LOC Counting Standard. Notes: -Your program should accept as input the name of a file that contains source code. You are to read the file ar count the number of lines of code according to our LOC Counting Standard. You may assume that the source adheres to the LOC Coding Standard, i.e., this assignment should not determine if the coding standard has be followed Your program should produce output following the general format below. Please do not clutter your submitted results with extraneous output. 1.xls LOC is 2.xls LOC is 125 712

Answer 1

#include <fstream>
#include <iostream>
using namespace std;

class Line_count
{
string line;
ifstream file_to_read;
public:
int read_file(string fname)
{
int i=-1;
file_to_read.open(fname);
if (!file_to_read.is_open())
{
   cout << " File not found " << endl;
   return -1;
}
else
{
i=0;
while ( getline (file_to_read,line) )
{
if(line.substr(0,2)!="//" && line.length() !=1) // check for comment and check for empty string which has length 1
i=i+1;
}
file_to_read.close();
}
return i;
}
};
int main ()
{
char file_name[10][20];
int loc[10];
int i=-1;
Line_count L;
char ans;
do
{
i=i+1;
cout<<" Enter file name :: ";
cin>>file_name[i];
loc[i]=L.read_file(file_name[i]);
cout<<" Wist to continue reading file :: (Y/N) ";
cin>>ans;
}while(ans!='N');
for(int j=0;j<=i;j++)
{
if(loc[j]==-1)
cout<<" "<<file_name[j]<<" not found ";
else
cout<<" "<<file_name[j]<<" LOC is "<<loc[j];
}
return 0;
};

Output

Enter file name :: 1.xls File not found Wist to continue reading file Enter file name :: my2.txt Wist to continue reading file (Y/N) Y (Y/N) N 1.xls not found my2.txt LoC is 10