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uepiuymenld-57211922315837568078877151038eISON-97813371142648ad-38416 NDTAP 8: Mastery Exercise Compute the value of the t-test statistic (Enter negative values as negative numbers). (to 4 decimals) What is the p-value? p-value is -Select your answer- What is your conclusion? We - Select your answer Ho e. Use the F-test to test the hypotheses in part (d) at a 0.10 level of significance. Present the results in the analysis of variance table format Iculate the Sum of Squares (to 1 decimal), the Mean Squares (to 1 decimal), and the F ratio (to 2 decimals) Degrees Sum of Mean SquareF p-value (to 4 decimals) Source of of Squares (to 1 (to 2 Variation Freedom (to 1 decimals) deimals) decimals) Regression Error Total What is the p-value? p-value is-select your answer- What is your concusion, based on this F testi Wei -select your answer , ▼ | Ho
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(x-x) 60.8400 33.6400 4.8400 17.6400 51.8400 168.8000 (x-x)(y-y) -104.5200 -124.1200 11.8800 -73.9200 -162.7200 -453.4000 S.No (y-y) 4 52 179.5600 457.9600 29.1600 309.7600 510.7600 1487.2000 SSY 2 14 16 19 21 16 193 38.6000 Total Mean 11.8000 sample size: here n- 38.6000 11.8000 from above 168.8000 Σ(X-X) (Yi-Y)- -453.4000 slope- 2.68602 intercept- 70.29502 hence line equation: 70.295 -2.686 x SSE- SSR 269.3590 SSR-b1*Sxy 1217.841 total sum of square SST 1487.2000 error Variance σ2- S-SSE/(n-) 89.7863 std error ơ 9.4756 null hypothesis Alternate Hypothesis for 0.05 level,two tailed test and n-1 3 degree of freedom, critical t- Decision rule 3.1824 reject Ho if absolute value of test statistic t>3.182 estimated standard error of slope se(B1) 0.7293 test statt- /se(P) 3.683

a)

s2 =89.79

b)

s=9.48

c)

sb1 =0.7293

d)

test statistic -3.6829

p value =0.025 <p vlaue <0.05

we reject Ho

e)

Source DF SS MS F
regression 1 1217.8 1217.8 13.56
Residual error 3 269.4 89.8
Total 4 1487.2

p vlaue 0.025 <p <0.05

reject Ho

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