Here we have to find p value Interval corresponding to given t value.
Here,
t value = 1.945
n= 28
Degrees of freedom, df = (n-1)= 27
Hence, using a t table and checking the value for df=27 which gives us two smallest bounds that contain our t value = 1.945
We get the interval ( 1.703 , 2.052 ) that contains our t value .
Further the p values corresponding to them are
0.10 and 0.05 respectively.
Hence, the interval of p value is
( 0.05 , 0.1 )
Hence, Option (c) 0.05 < p value < 0.1 is the correct alternative.
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