al
using work-energy theorem
W = change in kE
q V = 0.5 m ( v^2 - u^2)
1.6* 10^-19* V = 0.5* 9.11* 10^-31* ( (5.4* 10^6)^2 - ( 1.02* 10^5)^2)
V = 82.985 V
b)
x= 2cm is at higher potential
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An electron moving parallel to the x axis has an initial speed of 5.40 x 106...
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thanks you so much for your help in advance, if you could do
both that would be so helpful as i am out of questions, thank you
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