Homework Answers
4a) [H+] = 10-pH = 10-9.76 = 1.74×10-10 M
[OH-] = Kw/[H+] = 10-14/1.74×10-10
= 5.75×10-5 M
b) [OH-] = 7.2×10-3 M
[H+] = Kw /[OH-] = 10-14/7.2×10-3 = 1.39×10-12 M
pH = - log[H+] = - log(1.39×10-12)
= 11.86
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