1268365
Please solve it step by step
Given:
p + q + r = x*s -----> 1
q + r + s = y*p ------> 2 and p, q, r are not coplanar.
Eqn. 2 can be re-written as s = y*p - q - r -------> 3
Put Eqn. 3 in Eqn 1,
p + q + r = x*(y*p - q - r)
=> p( 1 - x*y ) + (1+x)* (q+r) = 0 Since, p, q, r are not coplanar => a*p + b*q + c*r = 0 only if a,b,c each is Zero. Making p,q,r independent vectors.
=> 1 + x = 0 and 1 - x*y = 0
=> x = -1 and 1 - (-1)*y = 0 => y = -1.
Substitute x in Eqn. 1 to get p + q + r + s = 0
As the vector itself is zero vector => it's magnitude i.e: |p + q + r + s| = 0
k(q)^2 / r = mv^2 please solve for v where k = 8.99x10^9 C, q = 10x10^-6 C, r = 0.055m, m = .001g. This problem is solving for electric potential energy and electric potential the right answer is V = 4.04x10^3 m/s. But I keep getting the wrong answer please do a step by step to show me thank you.
step by step please.
30. Let p and q denote quaternions and let a,b E R. Show that (b) (ap + bq)apbq (c) N(q) = qq* = qq (d) pq)* = q*p* [Hint: First show that (iq)* =-qi, (jq)* =- (kq)* =- (b).] (e) N(pq) -Np)N() [Hint: (c) and (d).] of k. q J, and g K, and then use
please provide step by step instructions to solve this
problem
Q 10 Let p be the circle of radius 2 centered at (0,2). What is the image of the point (0, 1) under inversion through p? What is the image of the circle 2+ (+5)2 36 under inversion through p?
Find the area of APQR. P(1, 0, 1), Q(0, 1, 0), R(4, 9, 10) Need Help? Read It Watch It Talk to a Tutor Show My Work (Optional) Submit Answer [-/2 Points] DETAILS SPRECALC7 9.5.029. MY NOTES AS Three vectors u, v, and w are given. u = (1, 2, 3), v = (-3, 2, 1), w = (0,4, 5) (a) Find their scalar triple product u. (V x W). (b) Are the vectors coplanar? Yes NO If not, find...
1607273
Please solve it step by step
Comprehensions (Q.305 to Q.307) Let the lines represented by the equation x2ya-x2 +1 0 formed a square ABCD. A point 'P' is taken on the same plane of square such that atleast two sides of all the triangles PAB, PCD and PDA are equal. The number of possible position of the pont 'P (A) 1 305. (B) 5 (C) 17 (D) 9 For all the possible position of point 'P. How many of...
Q2. Let u and v be non-parallel vectors in Rn and define Suv (a) Does the point r lie on the straight line through q with direction vector p? (b) Does the point s lie on the straight line through q with direction vector p? (c) Prove that the vectors s and p -r are parallel. (d) Find the intersection point of the line {q+λ p | λ E R} and the line through the points u and v. Q3....
my teacher gave me this problem with a few different twists.
for example this one says the charge is diteibuted as p=Q/r and
then in my other problem he put p=Qr and another one he put
p=Q/r^2.
my question is can you please explain how this changes the
formula to solve this problem or better said can you please show it
step by step for the different variations so when i get something
on the exam i fully understand what...
please in java or python truth tables for the following...please #1 p -> q q -> r therefor: p -> r #2 p -> (q or r) q and ~r Therefore: p #3 p or q (p and q) -> r q and ~r Therefor: ~p
HOMEWORK No. 4 1) If P, Q and S are vector forces and If P --2i+ 3j-4k and P Q=-i-j+kand S -3j MFI a) Find P.Q P -2 3-4 Q= 2X-D 311)+eD P.Q=-5 1 b) Find PX Q J K -2 3 -4 -1-1 1 fxQ=(5-)i +(-2-0j+(2-DK PxQ=-i-uj +5K c) Find Angle 31COS0 IG-N122 EN3 d) Unit Vector Q e) Find (P x Q).S (-i-aita = 13 f) Provide a graphical interpretation of the quantity (Px Q) . S g)...
Consider the points: P (-1,0, -1), Q (0,1,1), and R(-1,-1,0). 1.) Compute PQ and PR. 2.) Using the vectors computed above, find the equation of the plane containing the points P, Q, and R. Write it in standard form. 3.) Find the angle between the plane you just computed, and the plane given by: 2+y+z=122 Leave your answer in the form of an inverse trigonometric function.