Calculate the equilibirum expression of a 1:1 enzymatic reaction
where A goes to B, that has a
G=-15.52 kJ/mol at 298.15 K.
k=e^-(
G/RT)
I got K=1.006 but my professor doesn't like that answer for some reason
Calculate the equilibirum expression of a 1:1 enzymatic reaction where A goes to B, that has...
Calculate the value of Kp for the reaction $$2N2(g)+O2(g) 2N2O(g) at 298.15 K and 1273 K. Thermodynamic data for N2O(g) are: ΔH°f = 82.05 kJ/mol; S° = 219.9 J/mol ·K; ΔG°f = 104.2 kJ/mol. Pt 1: 298.1K Pt 2: 1273 K
Calculate the standard Gibbs energy of the following reaction at T = 298.15 K using the data given below. 2 CH3CHO(g) + O2(g) ® 2 CH3COOH(l) Som(CH3COOH(l)) = 159.8 J K–1 mol–1 DfHo(CH3COOH(l)) = –484.5 kJ mol–1 Som(CH3CHO(g)) = 250.3 J K–1 mol–1 DfHo(CH3CHO(g)) = –166.19 kJ mol–1 Som(O2(g)) = 205.14 J K–1 mol–1
I changed around the numbers a little from the original
problem, so if for some reason they dont work thats why, but i
would like to be able to follow what you did and how you did it so
i can complete the actual problem.
R-8.315 J/mol K-0.008315 kJ/mol K and T = 298 K (standard conditions) AG"=-RT In Kca and AG = AG* + RT In Q Raindrop + ATP Raindrop-1-phosphate + ADP Using the information below, calculate I)...
Consider the following reaction: CO2(g)+CCl4(g)⇌2COCl2(g). Calculate ΔrGfor this reaction at 125 ∘Cunder the following conditions. Part A PCO2=0.125 bar PCCl4= 0.185 bar PCOCl2=0.750 bar i understand what to do but for some reason they are saying my answer is incorrect... Answer: 57.161 kJ/mol
Given the information below,
calculate ∆?∘?,298.15? and ∆?∘?,400? for the following
reaction:
??(?) + 2???(?) → ?2(?) + ????2(?)
Assume that heat capacities are constant over the desired
temperature range. All molar enthalpies of formation are at
298.15K.
∆?∘ Mg(g) ? = 147.1 kJ/mol
∆?∘ HCl(g) ? = -92.3 kJ/mol
∆?∘ H2(g) ? = 0 kJ/mol
∆?∘ MgCl2(s) = -641.3 kJ/mol
Cp,m Mg(g) = 20.8 J mol-1 K-1
Cp,m HCl(g) = 29.1 J mol-1 K-1
Cp,m H2(g) = 28.8 J...
I have the answer I just need help explaining. I got the
reaction I wanted but my O2’s did not cancel like they
should.
18. Calculate AHnn for the following reaction: given the following: 4 B(s)+3 02(g) 2 B,03(s) AH- -2543.8 kJ AH -241.8k AH -2032.9 kJ H2g) + 1/2 O2(g) H2(g) B2Ho(g) +3 O2(g) B20,(s) +3 H20(g) a. -752.7 k b. -4030.2 kJ c. -4818.5 kJ d. +35.6 kJ e. +1280.2 kJ 19. What is STP (standard temperature and...
Please, I need help with my homework! Consider the reaction 2CO2(g) + 5H2(g)=C2H2(g) + 4H2O(g) for which ΔH° = 46.50 kJ and ΔS° = -124.8 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 2.230 moles of CO2(g) react under standard conditions at 298.15 K. ΔSuniverse _________ = J/K (2) Is this reaction reactant or product favored under standard conditions? _________ (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by...
1)
What is the value of Kc for the following reaction? (Calculate)
2) A reaction has an activation energy of 123 kj / mol and a K
of 0.200s ^ -1 to 311K. At what temperature will the constant be
twice that of 311k?
Fyi: “Ecuacion de” means Equation of
2C0(g) + O2(g) → 2CO2(g) CO2(g) → CO(g) + ½Oz(g) Kc = 5.0 x 1018 a 25°C Kc=??? (CALCULARLA) a 25 °C E, (1 R T X-8314 Ecuación de Arrhenius:...
In a reaction vessel @ 310 K, an equilibrium mixture is found to contain: 0.0370 M PCl3, 0.0174 M Cl2 and 1.316 M PCl5. PCl3 (g) + Cl2 (g) ⇋ PCl5 (g) Calculate Kp for the reaction. I did this, and used the equation (1.316 M PCl5) / (.0370 M Cl3 * .0174 M Cl2) = 2044 = 2040 with sig figs. Then because the delta n is -1 because of the coefficients, I used the equation (2040) / (.08206 *...
We didn't go over this in lecture/no where in my
notes... is there an equation I use?
The following reaction has the thermodynamic values at 298 K: AH° = -136.9 kJ/mol and AS° = -120.6 J/mol K. H2C=CH2 (9) + H2(g) - H3C-CH3 (9) kJ/mol. a. Calculate AGⓇ at 298 K for this reaction in kJ/mol (Enter your answer to four significant figures.): b. The reaction is c. The reaction is Submit Answer Try Another Version 10 item attempts remaining