Question

Quiz i Help Complete the following probability table. (Round Prior Probability and Posterior Probability answers to 2 decimal places and Joint Probability answers to 4 decimal places.) Prior Probabilities P(B) P(B ) Total Conditional Probabilities Joint Probability 0.51 PAB) 0.14 P(ANB) PAB^c) 0.36 PIAN B\c) PA) Posterior Probabilities P(BIA) P(BACA) Total

Answer 1

Answer:

Given that:

PB) = 0.51, P(AB) = 0.14,
hence
P(ANB) = 0.51 * 0.14 = 0.0714

P(BC) = 0.49

P(A B ) = 0.36
hence
P( A BC) = 0.49 *0.36 = 0.1764

Total = 1

Now,

P(A) = P(ANB) + P(A BC)

P(A) = 0.0714+ 0.1764

P(A) = 0.2478

Hence,

PBNA) P(BA) = ? P(A)

P(BA) - 0.0714 0.2478

P( B A) = 0.28

P(BNA) P(BCA) = 1 P(A)

0.1764 P(BCA) = 0.2478

P(BCA) = 0.72

Total = 1