9.29 Calculate the molar concentration of H3O+ in water solutions with the following OH- molar concentrations:...
9.29 Calculate the molar concentration of H3O+ in water solutions with the following
OH- molar concentrations:
a) 1.0 x 10^-5
b) 3.4 x 10^-4
c) 8.3 x 10^-9
d) 0.072
e) 3.2
Homework Answers
a)
we have below equation to be used:
[H3O+] = Kw/[OH-]
Kw is dissociation constant of water whose value is 1.0*10^-14 at 25 oC
[H3O+] = (1.0*10^-14)/[OH-]
[H3O+] = (1.0*10^-14)/1.0E-5
[H3O+] = 1.0*10^-9 M
Answer: 1.0*10^-9 M
b)
we have below equation to be used:
[H3O+] = Kw/[OH-]
Kw is dissociation constant of water whose value is 1.0*10^-14 at 25 oC
[H3O+] = (1.0*10^-14)/[OH-]
[H3O+] = (1.0*10^-14)/3.4E-4
[H3O+] = 2.941*10^-11 M
Answer: 2.9*10^-11 M
c)
we have below equation to be used:
[H3O+] = Kw/[OH-]
Kw is dissociation constant of water whose value is 1.0*10^-14 at 25 oC
[H3O+] = (1.0*10^-14)/[OH-]
[H3O+] = (1.0*10^-14)/8.3E-9
[H3O+] = 1.205*10^-6 M
Answer: 1.2*10^-6 M
d)
we have below equation to be used:
[H3O+] = Kw/[OH-]
Kw is dissociation constant of water whose value is 1.0*10^-14 at 25 oC
[H3O+] = (1.0*10^-14)/[OH-]
[H3O+] = (1.0*10^-14)/0.072
[H3O+] = 1.4*10^-13 M
Answer: 1.4*10^-13 M
e)
we have below equation to be used:
[H3O+] = Kw/[OH-]
Kw is dissociation constant of water whose value is 1.0*10^-14 at 25 oC
[H3O+] = (1.0*10^-14)/[OH-]
[H3O+] = (1.0*10^-14)/3.2
[H3O+] = 3.1*10^-15 M
Answer: 3.1*10^-15 M
Add Answer to:
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