Question

Make a function dict build(keys, values) which takes as argument two lists, one containing keys, one values to be put into a dictionary (in order). If the lists are of the same length put them into a dictionary form, and return the dictionary from the function. Otherwise return the keyword None from the function. For example: Test print(di ct_build(['a', 'b' , 'c'], [1,2,3])={ 'a': 1, 'b': 2, 'c': 3

Answer 1

def dict_build(lst1, lst2):

d = {}

if len(lst1) != len(lst2):

    return None

else:

    index = 0

    while index < len(lst1):

      d[lst1[index]] = lst2[index]

      index+=1

return d

print(dict_build(['a','b','c'],[1,2,3]))

print(dict_build(['a','b','c'],[ ]))

---------------------------------------------------------

SEE OUTPUT

Files : Python 3.7. [GCC 6.3.0 . {'a': 1, 'b None main.py Nm main.py B D saved 1 def dict_build(isti, ist2): d = {} if len(Isti) != len(lst2): return None else: index = 0 while index < len(lsti): d[lsti[index]] = lst2[index] index+=1 na return d 13 print(dict_build(['a','b', 'c'],[1,2,3])). print(dict_build(['a','b', 'c'], [ ])). 14 15

Thanks, PLEASE COMMENT if there is any concern. PLEASE UPVOTE