A 1.70 kg object is subjected to three forces that give it an acceleration a =...
Chapter 05, Problem 008 and A 1.90 kg object is subjected to three forces that give it an acceleration a = (1.30 m/s2)+ (6.30 m/s2 )). 1 two of the three forces are 7, = (23.0N) + (10.0N)) . 7,- (14.0N)i + (9.40N)), and (a) the x component and (b) tha y component of the the third force. (a) Number Units (b) Number Units
A 20-kg object is subjected to three forces which produce an acceleration a = -8 m.s-2 i + 6.0 m.s-2j on the object. Two of the forces are: F1 = 3.0 N i + 16.0 N j F2 = -12.0 N i+ 8.0 N j Find the third force.
Can someone help me with college physics question.
Three forces act on a 2.00-kg object at angles theta_1 = 40.0 degree, theta_2 = 60.0degree, and = 20.0degree as shown in Figure 4-29. Find the magnitude of F_2 and F_3 if the magnitude of F_1 is 1.00 N and the acceleration of the object is 1.50 m/s^2 toward the +x direction.
A 10 kg object on a frictionless table is subjected to two horizontal forces, F1 and F2, with magnitudes F1 = 22 N and F2 = 38 N, as shown in Figure 4-28. 10kg 30 Figure 4-28 (a) Find the acceleration a of the object (0.3 (b) A third force F3 is applied so that the object is in static equilibrium. Find F3 x i)m/s2 i1.64545 X (-41 x i) N |-32.909
A 10 kg object on a frictionless table...
A 5-kg object is subjected to two forces F1 = 5 N i + 12 N j and F2 = -10 N i + 7 N j. (a) What is the net force on the object?, (b) What is the acceleration produced by this net force? (c) If the object is at rest at the origin at t = 0, where is the object at time t = 5.0 s?
009 (part 1 of 3) 10.0 points A 4.8 kg object is subjected to two forces, F(2.3 N) i (-2.6 N) j and F (4.9 N) +(-11.9 N) . The object is at rest at the origin at time t -0. What is the magnitude of the object's ac- celeration? Answer in units of m/s?. 010 (part 2 of 3) 10.0 points What is the magnitude of the velocity at t- 3.8 s ? Answer in units of m/s. 011...
You are told that an object has zero acceleration. Two forces on the object are: F_1 has magnitude 2.4 N at 45 degrees above the +x-axis and F_2 has magnitude 4.8 N at 37 degrees below the -x-axis. What is the third force that must be acting on the object? THE ANSWER ALREADY PROVIDED IS CONFUSING, I THINK A) The vector F_3 has an x-component 5.5 N in the -x-direction and a y-component 4.6 N in the -y-direction. B) The...
Two horizontal forces act on a 2.0 kg chopping block that can slide over a friction less kitchen counter, which lies in an xy plane. One force is F_1 = (3.0 N)i + (4.0 N)j. Find the acceleration of the chopping block in unit-vector notation when the other force is (a) F_2 = (-3.0 N)i + (-4.0 N)j. (b) F_2 = (-3.0 N)i + (4.0 N)j, and (c) F_2 = (3.0 N)i + (-4.0 N)j.
Static Equilibrium of a Particle
A particle is subjected to three forces, F_1, F_2 and F_3. Forces and F_1 F_2 are defined with respect to the x and y axes as: Magnitude of F_1 = 9N Magnitude of F_2 = 10N Alpha = 57 degree beta = 59 degree Matlab input: Fl_mag = 9; F2_mag = 10; alpha = 57; beta = 59; Determine the magnitude and direction (angle 7) of F3 to maintain static equilibrium of the particle: Magnitude...
Three forces, F_1 = 40 N, F_2 = 20 N and F_3 = 10 N, are acting on a block of mass 4 kg as shown. The block is sitting on a horizontal surface with coefficient of kinetic friction mu_k = 0.12. The angle between F_1 and F_2 is 30 degree. What is the magnitude of: a) the friction force k_k? b) the resulting acceleration of the block in x-axis?