Question

Assignment > Open Assignment PRINTER VERSION BACK NEXT Chapter 5, Section 5.3, Question 03 Determine 4" (xo), '" (x0) and 6" (ao) for the given point x, if y = 4 (2) is a solution of the given initial value problem. y" + 6x²y' + (sin x)y= 0, y(0) = 20, y' (O) = a1 ASSIGNMENT RESOURCES WP8 Chapter 5, Section 5.1, Question 01 Chapter 5, Section 5.1. Question 03 Chapter 5, Section 5.1. Question 07 * Chapter 5, Section 5.1, Additional Question 01 Chapter 5, Section 5.2, Question 12a * Chapter 5, Section 5.2,. Question 13a Chapter 5, Section 5.3, Question 01 Chapter 5, Section 5.3, Question 03 Enter your answers using an, al. Equation Editor Common Ω Matrix en Va Review Score Review Results by Study Objective ad Va av lal ali u * o sin(a) Sec(a) sin ? (a) cos(a) cscla) cos? (a) tana cot(a) tan-(a) fdx | fdx 4" (20) =

Answer 1

þ"(No) +622 6' (Ho) + sin no) $ (20)=0 , 0"(X) + 6 to y'( Mo) + sin(no). Y CO )=0 As, Ho=o im this IVP: $" (Mo) + 6. 07. y'(o) + sin lo).y(0)=0 i, o" (lo)=0 * Now, differentiating the given egn: y" + 60² y" + 12xy' + (sina) y' + (COSH)y=0 i, y'"+682y" +(12x+ sin(a)) y '+(cosa)y=0... (1)

ger ." ( Mo) +62 "(M.) + (12.10 + sin(no)) $(10) + (ros no ) $(Mo) = 0 i !" (no) t boot. f"(Ho) + (12.00 + sino y/10) + (cos(o)). y (0)=0 f" (No) toto + 1x ao = 0 wis '" (40) = - do Now differentiating (i) we geti y + 6 x y"+(240+ sin(a)) y" + (12 + 2 cosx) y -(sina.)y=0 i piv (80) + 6 10 !" (0) + (2400+ sin o)) "106) + (12+ 2003c0)) $(x0) - King opene) - 0 ie, div (Ho) + 6.02 $" (Ho) + (axotsino) &" (0) + (12+2 coso) f'(o) (sino) y (o)=0 i, piv (Ho) toto + 14xa,-0=0 i, biv (no) =-14 a