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A cylindrical insulated wire of diameter 6.0 mm is tightly wound 150 times around a cylindrical core to form a solenoid with adjacent coils touching each other. When a 0.20 A current is sent through the wire, what is the magnitude of the magnetic field on the axis of the solenoid near its center? (μ 0 = 4π × 10-7 T · m/A)
| 5.7 × 10-5 T | |
| 1.2 × 10-5 T | |
| 2.1 × 10-5 T | |
| 4.2 × 10-5 T | |
| 9.8 × 10-5 T |
given that
a = 0.006 m
N = 150
L = N*a = 150*.006 = 0.9 m
magnetic field on the axis of the solenoid near its center is
B = u0*N*i / L
B = 4*3.14*10^(-7)*150*0.2 / 0.9
B = 4.2*10^(-5) T
B = 4.2*10^(-5) T
Please show all work and specify the correct answer at the bottom. Do not put down...
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