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Please show all work and specify the correct answer at the bottom. Do not put down...

Please show all work and specify the correct answer at the bottom. Do not put down an answer that is not one of the choices.

A cylindrical insulated wire of diameter 6.0 mm is tightly wound 150 times around a cylindrical core to form a solenoid with adjacent coils touching each other. When a 0.20 A current is sent through the wire, what is the magnitude of the magnetic field on the axis of the solenoid near its center? (μ 0 = 4π × 10-7 T · m/A)

5.7 × 10-5 T
1.2 × 10-5 T
2.1 × 10-5 T
4.2 × 10-5 T
9.8 × 10-5 T
0 0
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Answer #1

given that

a = 0.006 m

N = 150

L = N*a = 150*.006 = 0.9 m

magnetic field on the axis of the solenoid near its center is

B = u0*N*i / L

B = 4*3.14*10^(-7)*150*0.2 / 0.9

B = 4.2*10^(-5) T

B = 4.2*10^(-5) T

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