
Study the equivalent resistance readings for the series circuits.Can you come up with a rule for the equivalent resistance of a series circuit with two resistors? For each of the three series circuits, compare the experimental results with the resistance calculated using your rule. Consider tolerance of each resistor using the minimum and maximum values. Lastly, calculate the equivalent resistance of the circuit for each of the three parallel circuits.
Yes the rule for equivalent resistors in series is
R(eq) = R(1) + R(2)+.....
Beacuse the potential drop across 1st resistor will IR(1). The potential drop across second resistor will be IR(2) and son on. Note the current in both the resistors will be the same since they are in series.
Total potential drop should equal the potential of the battery = V
Hence V= I( R(1) + R(2)) hence equivalent resistance is R(eq)= R(1) + R(2)
Study the equivalent resistance readings for the series circuits.Can you come up with a rule for...
Learning Goal:
To learn to calculate the equivalent resistance of the circuits
combining series and parallel connections.
Resistors are often connected to each other in electric
circuits. Finding the equivalent resistanceof
combinations of resistors is a common and important task.
Equivalent resistance is defined as the single resistance that can
replace the given combination of resistors in such a manner that
the currents in the rest of the circuit do not change.
Finding the equivalent resistance is relatively straighforward if...
Pease answer questions 4 and 5! Thank you so much!
4. Connect the 2nd resistor in parallel with the 1st
resistor and connect that combination to the battery.
Measure
the following:
The
current passing through the R1, I1 = ___0.0058____ A
The
current passing through the R2, I2 = ___0.0031____ A
The
current supplied by the battery, I = ___0.0092____ A
Calculate I1 + I2 = ____________ A
Is the following statement true? I = I1 +...
Answer 4 & 5 please! thank
you!
R values =
Resistor value, R1 = 990 Ohms
Resistor value, R2 = 2050 Ohms
4. Connect the 2nd resistor in parallel with the 1st
resistor and connect that combination to the battery.
Measure
the following:
The
current passing through the R1, I1 = ___0.0058____ A
The
current passing through the R2, I2 = ___0.0031____ A
The
current supplied by the battery, I = ___0.0092____ A
Calculate I1 + I2 =...