An electron travels at a speed of 1.85 × 104 m/s through a uniform magnetic field...
An electron travels at a speed of 1.85 × 104 m/s through a uniform magnetic field whose magnitude is 1.20 × 103 T. What is the magnitude of the magnetic force on the electron if its velocity vector and the magnetic field vector are perpendicular to each other?
Homework Answers
F = QVB sin theta
F = QVB sin 90
F = 1.6*10^-19*1.85*10^4*1.2*10^3
F = 3.55*10^-12 N
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